Optimal. Leaf size=439 \[ \frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}-\frac {\left (128 a^4-144 a^2 b^2+21 b^4\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{280 \left (a^2-b^2\right ) d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}+\frac {2 a \left (8 a^2-3 b^2\right ) F\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{35 d \sqrt {a+b \sin (c+d x)}}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 \left (a^2-b^2\right ) d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (a b \left (32 a^4-59 a^2 b^2+27 b^4\right )-\left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)\right )}{280 \left (a^2-b^2\right )^2 d} \]
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Rubi [A]
time = 0.59, antiderivative size = 439, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 8, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {2770, 2940,
2945, 2831, 2742, 2740, 2734, 2732} \begin {gather*} \frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{70 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} F\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{35 d \sqrt {a+b \sin (c+d x)}}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 d \left (a^2-b^2\right )}-\frac {\left (128 a^4-144 a^2 b^2+21 b^4\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{280 d \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (a b \left (32 a^4-59 a^2 b^2+27 b^4\right )-\left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)\right )}{280 d \left (a^2-b^2\right )^2}+\frac {\sec ^7(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^{3/2}}{7 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 2732
Rule 2734
Rule 2740
Rule 2742
Rule 2770
Rule 2831
Rule 2940
Rule 2945
Rubi steps
\begin {align*} \int \sec ^8(c+d x) (a+b \sin (c+d x))^{5/2} \, dx &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}-\frac {1}{7} \int \sec ^6(c+d x) \sqrt {a+b \sin (c+d x)} \left (-6 a^2+\frac {3 b^2}{2}-\frac {9}{2} a b \sin (c+d x)\right ) \, dx\\ &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}+\frac {1}{35} \int \frac {\sec ^4(c+d x) \left (\frac {3}{4} a \left (32 a^2-11 b^2\right )+\frac {21}{4} b \left (4 a^2-b^2\right ) \sin (c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx\\ &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 \left (a^2-b^2\right ) d}-\frac {\int \frac {\sec ^2(c+d x) \left (-6 a \left (8 a^4-11 a^2 b^2+3 b^4\right )-\frac {9}{8} b \left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx}{105 \left (a^2-b^2\right )}\\ &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 \left (a^2-b^2\right ) d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (a b \left (32 a^4-59 a^2 b^2+27 b^4\right )-\left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)\right )}{280 \left (a^2-b^2\right )^2 d}+\frac {\int \frac {-\frac {3}{16} a b^2 \left (32 a^4-59 a^2 b^2+27 b^4\right )-\frac {3}{16} b \left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)}{\sqrt {a+b \sin (c+d x)}} \, dx}{105 \left (a^2-b^2\right )^2}\\ &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 \left (a^2-b^2\right ) d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (a b \left (32 a^4-59 a^2 b^2+27 b^4\right )-\left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)\right )}{280 \left (a^2-b^2\right )^2 d}+\frac {1}{35} \left (a \left (8 a^2-3 b^2\right )\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}} \, dx-\frac {\left (128 a^4-144 a^2 b^2+21 b^4\right ) \int \sqrt {a+b \sin (c+d x)} \, dx}{560 \left (a^2-b^2\right )}\\ &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 \left (a^2-b^2\right ) d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (a b \left (32 a^4-59 a^2 b^2+27 b^4\right )-\left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)\right )}{280 \left (a^2-b^2\right )^2 d}-\frac {\left (\left (128 a^4-144 a^2 b^2+21 b^4\right ) \sqrt {a+b \sin (c+d x)}\right ) \int \sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}} \, dx}{560 \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}+\frac {\left (a \left (8 a^2-3 b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}\right ) \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}} \, dx}{35 \sqrt {a+b \sin (c+d x)}}\\ &=\frac {\sec ^7(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^{3/2}}{7 d}-\frac {\left (128 a^4-144 a^2 b^2+21 b^4\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{280 \left (a^2-b^2\right ) d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}+\frac {2 a \left (8 a^2-3 b^2\right ) F\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{35 d \sqrt {a+b \sin (c+d x)}}+\frac {3 \sec ^5(c+d x) \sqrt {a+b \sin (c+d x)} \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{70 d}-\frac {\sec ^3(c+d x) \sqrt {a+b \sin (c+d x)} \left (4 a b \left (a^2-b^2\right )-\left (32 a^4-39 a^2 b^2+7 b^4\right ) \sin (c+d x)\right )}{140 \left (a^2-b^2\right ) d}-\frac {\sec (c+d x) \sqrt {a+b \sin (c+d x)} \left (a b \left (32 a^4-59 a^2 b^2+27 b^4\right )-\left (128 a^6-272 a^4 b^2+165 a^2 b^4-21 b^6\right ) \sin (c+d x)\right )}{280 \left (a^2-b^2\right )^2 d}\\ \end {align*}
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Mathematica [A]
time = 4.20, size = 338, normalized size = 0.77 \begin {gather*} \frac {\frac {\left (\left (128 a^4-144 a^2 b^2+21 b^4\right ) E\left (\frac {1}{4} (-2 c+\pi -2 d x)|\frac {2 b}{a+b}\right )-16 a \left (8 a^3-8 a^2 b-3 a b^2+3 b^3\right ) F\left (\frac {1}{4} (-2 c+\pi -2 d x)|\frac {2 b}{a+b}\right )\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{a-b}+\frac {\sec (c+d x) (a+b \sin (c+d x)) \left (-32 a^3 b+27 a b^3+128 a^4 \sin (c+d x)-144 a^2 b^2 \sin (c+d x)+21 b^4 \sin (c+d x)+2 \left (a^2-b^2\right ) \sec ^2(c+d x) \left (-4 a b+\left (32 a^2-7 b^2\right ) \sin (c+d x)\right )-4 \left (a^2-b^2\right ) \sec ^4(c+d x) \left (a b+3 \left (-4 a^2+b^2\right ) \sin (c+d x)\right )+40 \left (a^2-b^2\right ) \sec ^6(c+d x) \left (2 a b+\left (a^2+b^2\right ) \sin (c+d x)\right )\right )}{a^2-b^2}}{280 d \sqrt {a+b \sin (c+d x)}} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1886\) vs.
\(2(477)=954\).
time = 27.70, size = 1887, normalized size = 4.30
method | result | size |
default | \(\text {Expression too large to display}\) | \(1887\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.18, size = 697, normalized size = 1.59 \begin {gather*} \frac {\sqrt {2} {\left (256 \, a^{5} - 384 \, a^{3} b^{2} + 123 \, a b^{4}\right )} \sqrt {i \, b} \cos \left (d x + c\right )^{7} {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) - 3 i \, b \sin \left (d x + c\right ) - 2 i \, a}{3 \, b}\right ) + \sqrt {2} {\left (256 \, a^{5} - 384 \, a^{3} b^{2} + 123 \, a b^{4}\right )} \sqrt {-i \, b} \cos \left (d x + c\right )^{7} {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) + 3 i \, b \sin \left (d x + c\right ) + 2 i \, a}{3 \, b}\right ) + 3 \, \sqrt {2} {\left (128 i \, a^{4} b - 144 i \, a^{2} b^{3} + 21 i \, b^{5}\right )} \sqrt {i \, b} \cos \left (d x + c\right )^{7} {\rm weierstrassZeta}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) - 3 i \, b \sin \left (d x + c\right ) - 2 i \, a}{3 \, b}\right )\right ) + 3 \, \sqrt {2} {\left (-128 i \, a^{4} b + 144 i \, a^{2} b^{3} - 21 i \, b^{5}\right )} \sqrt {-i \, b} \cos \left (d x + c\right )^{7} {\rm weierstrassZeta}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) + 3 i \, b \sin \left (d x + c\right ) + 2 i \, a}{3 \, b}\right )\right ) - 6 \, {\left ({\left (32 \, a^{3} b^{2} - 27 \, a b^{4}\right )} \cos \left (d x + c\right )^{6} - 80 \, a^{3} b^{2} + 80 \, a b^{4} + 8 \, {\left (a^{3} b^{2} - a b^{4}\right )} \cos \left (d x + c\right )^{4} + 4 \, {\left (a^{3} b^{2} - a b^{4}\right )} \cos \left (d x + c\right )^{2} - {\left ({\left (128 \, a^{4} b - 144 \, a^{2} b^{3} + 21 \, b^{5}\right )} \cos \left (d x + c\right )^{6} + 40 \, a^{4} b - 40 \, b^{5} + 2 \, {\left (32 \, a^{4} b - 39 \, a^{2} b^{3} + 7 \, b^{5}\right )} \cos \left (d x + c\right )^{4} + 12 \, {\left (4 \, a^{4} b - 5 \, a^{2} b^{3} + b^{5}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \sqrt {b \sin \left (d x + c\right ) + a}}{1680 \, {\left (a^{2} b - b^{3}\right )} d \cos \left (d x + c\right )^{7}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F(-1)]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \text {Hanged} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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